Hello, are you going to make a coil to produce a certain voltage? (because they are not available)?
Magnetude of induced e.m.f. or voltage = number of turns x the change in flux divided by the change in time.
If you can come up with some values, to plug into this formula.
#Number of turns can be wound.
The flux produced by the magnet, I beleive it is horse shoe magnet embedded in the flywheel.
(Not sure of the amount in webers)
#Change in time? I guess if engine in rotating at 3000rpm, you could work that out.
Just looked up in text book, with just one diode that is called a single phase half wave rectifier.
As Grumpy said, it is choppy dc, diode blocks the negative half cycle of the ac waveform produced.
Voltage across the load coil,(primary coil) would be, 0.45 x ac Voltage produced by your supply coil.
